Question

Question
Three forces P = 50 N
(towards East), Q = 100 N
(towards North), and R = 75 N
(towards South), are acting on
the member, their resultant is
nearer to
​

Answer 1

I think EAST IS RESULTANT

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Answer 2

Answer:

The resultant force for the given forces is 103.077.

Explanation:

Given are the three forces of magnitude  P = 50 N, Q = 100 N and            R = 75 N

Resolving the given (P,Q,R) forces into the standard axes of(i,j,k) as,

$P= 50N i\\Q=100N j\\R=75 N(-i)$

On solving the above resolved forces we get,

$F=(50-75)i +100j\\F=-25i+100j$

Resultant Force for the given Force,

$F_{res}=\sqrt{-(25)^{2} +(100)^{2} } \\F_{res}=\sqrt{10625} } \\F_{res}=103.077$

Hence, is 103.077 is the resultant force for the given forces .