Math, asked by vivekkumar8459, 7 months ago

Question=Three pipes A, B and C can fill an empty cistern in 15 hours, 10 hours and 6 hours respectively. In how much time will the cistern be filled, if all the three pipes work together?
Solution will be Step by Step —​

Answers

Answered by cjneha007
0

Answer:

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Step-by-step explanation:

Answer

Let it take x hours to fill the tank by all the three pipes.

Then work done by {A in x hours + B in (x - 1) hours + C in (x - 2) hours} = 1

⇒10x​+12(x−1)​+15(x−2)​=1

⇒6x+5(x−1)+4(x−2)=60

⇒15x−13=60⇒15x=73

⇒x=1573​=41513​=4hours+1513​×60min  =4hours52min.

The time in which the cistern was just filled is =4hours52min.

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