Question=Three pipes A, B and C can fill an empty cistern in 15 hours, 10 hours and 6 hours respectively. In how much time will the cistern be filled, if all the three pipes work together?
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Let it take x hours to fill the tank by all the three pipes.
Then work done by {A in x hours + B in (x - 1) hours + C in (x - 2) hours} = 1
⇒10x+12(x−1)+15(x−2)=1
⇒6x+5(x−1)+4(x−2)=60
⇒15x−13=60⇒15x=73
⇒x=1573=41513=4hours+1513×60min =4hours52min.
The time in which the cistern was just filled is =4hours52min.
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