Question

Question


trolley, while going down an inclined plane, has an acceleration of 2 cm s-2. What will be its velocity 3 s after the start?


train is travelling at a speed of 90 km h–1. Brakes are applied so as to produce a uniform acceleration of –0.5 m s-2. Find how far the train will go before it is brought to rest.



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Answer 1

Answer:

question 1

Given,

initial velocity (u) = 0 (the trolley begins from the rest position)

Acceleration (a) = 0.02 ms-2

Time (t) = 3s

As per the first motion equation, v=u+at

Therefore, terminal velocity of the trolley (v) = 0 + (0.02 ms-2)(3s)

= 0.06 ms-2

Therefore, the velocity of the trolley after 3 seconds will be 6 cm.s-2

question 2

GIVEN

initial velocity (u) = 90 km/hour = 25 m.s-1

Terminal velocity (v) = 0 m.s-1

Acceleration (a) = -0.5 m.s-2

As per the third motion equation, v2-u2=2as

Therefore, distance traveled by the train (s) =(v2-u2)/2a

s = (02-252)/2(-0.5) meters

= 625 meters

The train must travel 625 meters at an acceleration of -0.5 ms-2 before it reaches the rest position.

FORMALS USED

v=u+at

v2-u2=2as

HOPE IT HELPS

Answer 2

Answer:

Explanation:

A trolley, while going down an inclined plane, has an acceleration of 2 cm s-2. ... Hence, the velocity of the trolley after 3 s from start is 6 cm/s.