Question

Question


Two bodies are dropped from two
different heights 'a' & 'b'. The ratio of the
time taken by the two to drop through
these distance will be​

Answer 1

Answer:

For a freely falling object :

a=g;

Initial velocity=u=0 m/s

g=9.8m/s²

from second equation of motion:S=ut+1/2 at²

for First object we get :

h1= gT1²/2

⇒T1=√2h1/g

For second object we get h2=gT2²/2

⇒T2=√2h2/g

T1/T2 =√h1/h2

But here h1= a and h2 =b

so, T1/T2=√a/b