Question

Question :
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➡️Two dice are numbered 1, 2, 3, 4, 5, 6 and 1, 1, 2, 2, 3, 3, respectively. They are thrown, and the sum of the numbers on them is noted. Find the probability of getting each sum from 2 to 9 separately.
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Answer 1

Answer:

Favourable outcomes =36

(1,1)(2,1)(3,1)(4,1)(5,1)(6,1)

(1,1)(2,1)(3,1)(4,1)(5,1)(6,1)

(1,1)(2,2)(3,2)(4,2)(5,2)(6,2)

(1,2)(2,2)(3,2)(4,2)(5,2)(6,2)

(1,3)(2,3)(3,3)(4,3)(5,3)(6,3)

(1,3)(2,3)(3,3)(4,3)(5,3)(6,3)

the probability of getting each sum from 2 to 9

Sum of 2=

36

2

=

18

1

Sum of 3=

36

4

=

9

1

Sum of 4=

36

4

=

9

1

Sum of 5=

36

6

=

6

1

Sum of 6=

36

6

=

6

1

Sum of 7=

36

6

=

6

1

Sum of 8=

36

4

=

9

1

Sum of 9=

36

2

=

18

1

.

Answer 2

Answer:

The probability of getting each sum from 2 to 9 is given above

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