Question :
Two identical copper spheres are put in contact the gravitational
force of attraction between them is
proportional to Nth power of their radius N is equal to
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Answer:
Gravitational attraction between two objects =
F = G M1 M2 / d²
where d = distance between the centers of mass of the two objects
= 2 R
F = G M² / (2R)² = (G M²/4) R⁻²
So the force α (2 R)⁻² or R⁻²
x = - 2
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