Math, asked by Anonymous, 2 months ago

Question:-

Two years ago. Dllip was three times as old as his son and two years hence, twice his age will be equal to five times that of his son. Find their present ages. Check your solution

Answers

Answered by mishthigarg80
0

Answer:

Two years ago, father was three times as old as his son and two years hence, twice his age will be equal to five times that of his son. Find their presents ages. Son's present age X = 14 years. Father's present age = 38 years.

Answered by Anonymous
2

Answer:

• Two years ago, father was three times as old as his son and two years hence, twice his age will be equal to five times that of his son.

•Son's present age X = 14 years.

•Father's present age = 38 years.

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