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Five times the 5 th term of an AP is equal to
ten times the 10th term. If the common
difference of the AP is 7, then find its 25th
term.
25th term = 70
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Answer: d = 7 (Given)
5th term = a5 = a+4d = a+28
10th term = a10 = a+9d = a+63
ATQ,
5(a5) = 10(a10)
5(a+28) = 10(a+63)
a+28 = 10(a+63) /5
a+28 = 2(a+63)
a+28 = 2a+126
0 = a+126-28
0 = a+98
-98 = a
25th term = a25 = a+24d
a25 = (-98) + 24*7
a25 = (-98) + 168
a25 = 70
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