Question

Question:Use suitable identities to find the following products : (I) (X+8) (X - 10) (II) (X+4) (X+10)



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Answer 1

Step-by-step explanation:

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Q:-Use suitable identities to find the following products : (I) (X+8) (X - 10) (II) (X+4) (X+10)

$\huge\tt\underline\blue{Answer </p><p> }$

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solving (I)

$⟹(x + 8)(x - 10)$

Here this identify is used:-

$⟹(x + a)(x - b) = {x}^{2} + (a + b)x + ab$

$⟹(x + 8)(x - 10) = {x}^{2} + (8 + ( - 10))x + - 8 \times 10$

$⟹ {x}^{2} - 2x - 80 = 0$

solving (ii)

$⟹(x + 4)(x + 10)$

$⟹(x + 4) (x - 10) = {x}^{2} + (4 + ( - 10))x + 4 \times - 10$

$⟹ {x}^{2} - 6x - 40 = 0$

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HOPE IT HELPS YOU..

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Thankyou:)

Answer 2

→ Solving (I)

$\tt{⟹(x + 8)(x - 10)}$

→ Here this identify is used:-

$\tt{⟹(x + a)(x - b) = {x}^{2} + (a + b)x + ab}$

$\tt{⟹(x+a)(x−b)= {x}^{2} }$

$\tt{⟹{x}^{2} + (8) + ( - 10)x + - 8 \times 10}$

$\tt{⟹(x+8)(x−10)= {x}^{2}}$

$\tt{⟹ {x}^{2} - 2x - 80 = 0</p><p>⟹x2</p><p>}$

$\ \tt{ \pink{→ Solving \: (ii)}}$

$\tt{⟹(x + 4)(x + 10)}$

$\tt{⟹{x}^{2} + (4 )+ ( - 10)x + 4 \times - 10}$

$\tt{⟹(x+4)(x−10)= {x}^{2} </p><p> }$

$\tt{⟹ {x}^{2} - 6x - 40 = 0}$