Question

Question:-
What is focal length of this curved surface.​

Answer 1

Answer:

Here is the solution

Explanation:

Equivalent power of combination,

P

eq

=2P

L

+P

M

=2(μ−1)(

R

1

)+0

The required focal length,

f=−

P

eq

1

=−

2(μ−1)

R

=−

2(1.5−1)

10

=−10cm

Answer 2

Answer:

The focal length of curved surface is 10cm

Explanation:

Given that,

Radius of curvature of this curved surface(R)=10cm

The equivalent power if this curved surface is given as follows-

$P_{eq} = 2 \times P = (u - 1)( \frac{2}{R} ) \\ = > \frac{1}{f} = (u - 1)( \frac{2}{R} )$

Here,Refractive index(u)=1.5

By substituting the known values we can find the focal length of this curved surface

$\frac{1}{f} = (1.5 - 1)( \frac{2}{10} ) = = > f = 10cm$

Therefore,The focal length of curved surface is 10cm

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