♠ QUESTION : What is the Moment of inertia of a rod of mass m, length l about an axis passing through its one end.?
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In the centre the moment of inertia would be ml²/12.
In second case, the moment of inertia is shifted to the end of the rod; which is at a distance of l/2 from the centre of the rod.
The formula to find the moment of inertia in such case is; I = ml²/12+m(h²)
h→ distance of the axis from the centre.
Therefore, I = ml²/12+m(l/2)²
I = ml²/12+ml²/4
I = ml²/3
Anonymous:
No.
sorry
just a minute
Ans is ML^2/3
i hadn't read that the axis was at its end.
hey , (ml^2/ 12) + (ml^2) / 4 = 4ml^2 . isn't it ?
Thanks..
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