Question

Question
X and Y are asked to write a program to sum the rows of a 2x2 matrix stored in an array A.
X writes the code (Code A) as follows:
for n = 0 to 1
sumRow1[n] = A[n][0] + A[n][1]
end
Y writes the code (Code B) as follows:
sum Row 1[0] = A[0][0] + A[0][1]
sum Row1[1] = A[1][0] + A[1][1]
Which of the following statements is correct about these codes if no loop unrolling is done by the compiler?
Code A would execute faster than Code B.
Code B would execute faster than Code A.
Code A is logically incorrect
Code B is logically incorrect​

Answer 1

Answer:

b faster than a

Code B would execute faster than Code A.

Answer 2

Code B would execute faster than Code A is correct about these codes if no loop unrolling is done by the compiler ( option b is correct answer)

• X writes the code (Code A) as follows:
• for n = 0 to 1
• sumRow1[n] = A[n][0] + A[n][1]
• Y writes the code (Code B) as follows:
• sum Row 1[0] = A[0][0] + A[0][1]
• sum Row1[1] = A[1][0] + A[1][1]
• Both Code A and Code B take two steps to complete the coding, and after that both them give the output.
• so, for that case we consider the overhead Looping matter to find out what code run faster.
• A technique for transforming loops called "loop unrolling" aids in streamlining a program's execution time. Iterations are essentially eliminated or decreased. When a loop is unrolled, loop control and loop test instructions are removed, which speeds up the programme.
• In Code B the number of overhead Looping is more than Code A.

Hence, Code B would execute faster than Code A

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