Question

Question: x²+3x+k=2
To Find k
(Don't remove this one as it appropriate question now, remove older one not this)

Answer 1

Answer:

Q; x²+3x+K=2

A; x(x+3)+K=2

=> (x+3)+K=2/x

=> K= 2/x-x+3

Answer 2

Answer:

The value of k= -10

Step-by-step explanation:

Given : Quadratic polynomial x²+3x+k

One of the root is 2

To find : The value of k

Solution :

Let the given quadratic polynomial be f(x)=x²+3x+k

Given one of the zero of the quadratic polynomial is 2.

Hence f(2)= 0

Put x = 2 in f(x), we get

f(2)=2²+3(2)+k

0=4+6+k

0=10+k

k+10=0

k=-10

Therefore, The value of k is -10.

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