Question

Question01:find the value of each of the following polynomials:(1)p(x)=3x^2-5x+4 at x=2
(2)Q(y)9y^4+5y+3 at y=1
Question02:find the zero of the polynomial in each of the following cases:
(a)p(x)=x+6
(b)p(x)=4x-5
(c)p(x)=2x+9​

Answer 1

Answer:

Q1

(i) p(x)=3x²-5x+4

p(2) =3(2) ²-5(2) +4

=3×4-10+4

=12-6

=6

(ii)q(y) =9y⁴+5y+3

q(1) =9(1) ⁴+5(1) +3

=9+5+4

=18