"Question18
Show that, cos30°+ sin60° / 1 + sin30° + cos60° = cos30°
Chapter6,T-Ratios of particular angles Exercise -6 ,Page number 288"
Answers
Answered by
3
HELLO DEAR,
R.H.S
(√3/2 + √3/2) / (1 + 1/2 + 1/2)
= 2√3/2 / (1 + 2/2)
= √3/2
WE KNOW THAT:-
L.H.S
COS30° = √3/2
HENCE, R.H.S = L.H.S
I HOPE ITS HELP YOU DEAR,
THANKS
R.H.S
(√3/2 + √3/2) / (1 + 1/2 + 1/2)
= 2√3/2 / (1 + 2/2)
= √3/2
WE KNOW THAT:-
L.H.S
COS30° = √3/2
HENCE, R.H.S = L.H.S
I HOPE ITS HELP YOU DEAR,
THANKS
Answered by
2
Hey there,
As we have learnt in this chapter, The values of Trigonometric ratios of particular angles are
cos30 = √3/2
sin60 = √3/2
sin30 = 1/2
cos60 = 1/2
Now,
Taking L. H. S,
cos30°+ sin60° / 1 + sin30° + cos60
= [ √3/2 + √3/2 ] / [ 1 + 1/2 + 1/2 ]
= [ √3 ] / 2
= √3 /2
Now, Taking R. H. S
= cos30
= √3/2
So, Here we see that Both L. H.S and R. H. S are equal, So L. H. S = R. H. S = √3/2
Finally, We proved that cos30°+ sin60° / 1 + sin30° + cos60° = cos30°
As we have learnt in this chapter, The values of Trigonometric ratios of particular angles are
cos30 = √3/2
sin60 = √3/2
sin30 = 1/2
cos60 = 1/2
Now,
Taking L. H. S,
cos30°+ sin60° / 1 + sin30° + cos60
= [ √3/2 + √3/2 ] / [ 1 + 1/2 + 1/2 ]
= [ √3 ] / 2
= √3 /2
Now, Taking R. H. S
= cos30
= √3/2
So, Here we see that Both L. H.S and R. H. S are equal, So L. H. S = R. H. S = √3/2
Finally, We proved that cos30°+ sin60° / 1 + sin30° + cos60° = cos30°
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