question2 please fast
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n21=sin 45÷sin 30=√2
n12=sin 30÷ sin 45=1÷√2
formula n21=sin theta1÷sin there
n12=sin theta2÷sin theta1
n12=sin 30÷ sin 45=1÷√2
formula n21=sin theta1÷sin there
n12=sin theta2÷sin theta1
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