"Question30
Using the formula, tan2A = 2 tan A / 1 - tan²A, find the value of tan 60° , it being given that tan 30° = 1 / √3 .
Chapter6,T-Ratios of particular angles Exercise -6 ,Page number 289"
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Answered by
70
aaaaaand the answer is = √3
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Answered by
60
Hey there!
Hey there !
Given Formula : tan2A = 2 tan A / 1 - tan²A
Also, tan30 = 1/√3
Required to find : tan60
Now,
Let A = 30 , 2A = 60°
tan2A = 2tanA / 1 - tan²A
tan60 = 2(tan30 ) / 1 - ( tan²30)
tan60 = 2(1/√3) / 1 -( 1/√3)²
tan60 = 2/√3 / 1 - 1/3
tan60 = 2/√3 / 2/3
tan60 = 2/√3 * 3/2
tan60 = √3
Therefore , tan60 = √3
Thanks for the question!
Hey there !
Given Formula : tan2A = 2 tan A / 1 - tan²A
Also, tan30 = 1/√3
Required to find : tan60
Now,
Let A = 30 , 2A = 60°
tan2A = 2tanA / 1 - tan²A
tan60 = 2(tan30 ) / 1 - ( tan²30)
tan60 = 2(1/√3) / 1 -( 1/√3)²
tan60 = 2/√3 / 1 - 1/3
tan60 = 2/√3 / 2/3
tan60 = 2/√3 * 3/2
tan60 = √3
Therefore , tan60 = √3
Thanks for the question!
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