Question

Question36 The number of zeros at the end of (2^123- 2^122 -2^121)(3^223-3^222-3^221) is

Answer 1

Answer:

option B, that is 1 zero.

Step-by-step explanation:

(2^123- 2^122 -2^121) (3^223-3^222-3^221)

= 2^121 ( 2^2 - 2 - 1 ) 3^221 ( 3^2 - 3 - 1)

= 2^121 (1) * 3^221(5)

= 2^121 * 3^221(5)

Hence, there is only one 5 which means one zero because 2*5=10 the number of 5 will be equal to the number of zero in the answer, no matter how much 3s or 2s are there in the question.

Answer 2

Answer:

Step-by-step explanation:

option B, that is 1 zero.

Step-by-step explanation:

(2^123- 2^122 -2^121) (3^223-3^222-3^221)

= 2^121 ( 2^2 - 2 - 1 ) 3^221 ( 3^2 - 3 - 1)

= 2^121 (1) * 3^221(5)

= 2^121 * 3^221(5)

Hence, there is only one 5 which means one zero because 2*5=10 the number of 5 will be equal to the number of zero in the answer, no matter how much 3s or 2s are there in the question.