"Question46
Prove the identity : (sec² θ - 1) cot² θ = 1
Chapter7,Trigonometric identities Exercise -7A , Page number 314"
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Answered by
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Hey there!
We will prove this by using identities.
We know that,
sec²A - tan²A = 1
Now,
sec²A - 1 = tan²A
Also, tanA * cotA = 1
--------------------------------------------------------------
Coming back to your question,
L. H. S
= (sec² θ - 1) cot² θ
= tan² θ * cot² θ
= ( tan θ * cot θ ) ²
= 1²
= 1
= R. H. S
Hence, (sec² θ - 1) cot² θ = 1
In this type of questions, we need to decide choose identity helps us. Trigonometry is simple and you can do it by understanding things well. This question will seem confusing if you write different identities .We could also have proved it by other means , But I proved it this way as it is of Trigonometric identities chapter.
We proved (sec² θ - 1) cot² θ = 1
We will prove this by using identities.
We know that,
sec²A - tan²A = 1
Now,
sec²A - 1 = tan²A
Also, tanA * cotA = 1
--------------------------------------------------------------
Coming back to your question,
L. H. S
= (sec² θ - 1) cot² θ
= tan² θ * cot² θ
= ( tan θ * cot θ ) ²
= 1²
= 1
= R. H. S
Hence, (sec² θ - 1) cot² θ = 1
In this type of questions, we need to decide choose identity helps us. Trigonometry is simple and you can do it by understanding things well. This question will seem confusing if you write different identities .We could also have proved it by other means , But I proved it this way as it is of Trigonometric identities chapter.
We proved (sec² θ - 1) cot² θ = 1
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