QUESTION5) Find the molecular weight of urea[CON2H4]. Find the % of nitrogen also.
[N=14, C=12 ,O=16 ,H=1] [3]
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Explanation:
the molecular weight of urea[CON2H4]
12+16+14×2+1×4
12+16+28+4
60a.m.u
percentage of nitrogen in urea[CON2H4]=
formula of nitrogen in urea=N2
molecular mass of N2
14×2
28a.m.u
percentage of nitrogen=molecular mass of nitrogen×100/molecular mass of urea
=28×100÷60
=46.666%(ans)
=
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