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I-x=50, ii-x=26, iii-x=90
l hope it help you
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(I) XY//BC
<XAB= alternate <ABC = 50
x =180 - (<ABC + < BAC) = 180 - (50 + 83) = 180 - 133 = 47
(iii) AB//CD and QP is the transversal
< CPD = 62 [ they are corresponding angles]
QP//RS and CD is the transversal
x = alternate <CPR = 62
hope my answer helps you!
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