Math, asked by newtonlaw60, 6 hours ago

Questions :

1) If 1.125 × 10^n = 0.001125 ,so find the value of n.

2) 9.68×9.68-3.18×3.18/(9.68+3.18)​

Answers

Answered by Anonymous
141

Solution :

1) If 1.125 × 10^n = 0.001125

RHS = 0.001125 ,

→ 1125/10⁶

→ 1125 × 10^-6

→ 1125 × 10^-3 × 10^-3

LHS = 1.125 × 10^n

→ 1125/10³ × 10^n

→ 1125 × 10^-3 × 10^n

•°• According to RHS, the value of n is - 3

2) 9.68×9.68-3.18×3.18/(9.68+3.18)

  • a² - b² = (a + b)(a - b)

→ 9.68×9.68-3.18×3.18/(9.68+3.18)

→ (9.68)² - (3.18)²/(9.68+3.18)

→ (9.68 + 3.18)(9.68 - 3.18)/(9.68+3.18)

  • Cancel (9.69 + 3.18)

→ 9.68 - 3.18

→ 6.5

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