Question

Questions 1
If Logx (1 / 8) = - 3 / 2, then x is equal to
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Answer 1

Answer:

$\red {Value \: of \: x } \green {= 4}$

Step-by-step explanation:

$Given \: log_{x} \left(\frac{1}{8}\right) = \frac{-3}{2}$

$\implies log_{x} 2^{-3} = \frac{-3}{2}$

$\implies 2^{-3} = x^{\frac{-3}{2}}$

$\implies (2^{2})^{\frac{-3}{2}} = x^{\frac{-3}{2}}$

$\implies 2^{2} = x$

$\implies x = 4$

Therefore.,

$\red {Value \: of \: x } \green {= 4}$

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Answer 2

Answer:

If Logx (1 / 8) = - 3 / 2, then x is equal to

Rewrite the logarithmic equations using exponential equation

x^logx(1/8)=x^-3/2

1/8=x^-3/2

8=x^3/2

cube root on both sides

2=x^1/2

x=2^2=4