Question

QUESTIONS
1. In the given figure, O is the centre of the circle and ZOAC = 60° and ZOBC= 70°. Find ZAOB.

(a) 130°
(c) 65°
(b) 80°
(d) 100°
​

Answer 1

Answer:

d 100°

Step-by-step explanation:

AO=OC=OB radii of same circle

OAC=OCA ISCOCLES TRIANGLE THEOREM

OCA =60°...... 1

SIMILARLY

OBC = OCB ISCOCLES TRIANGLE THEOREM

OCB = 70°...... 2

OCA+OCB =130°........ANGLE ADDITION PROP.

SUM OF ANGLES OF QUADRILATERAL=360

OAC + ACB + CBO +BOA =360

60 +70+130+ x = 360

x= 360-260

x=100°

AOB =100°

Answer 2

Answer:

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