Math, asked by Jyeshtha123, 1 year ago

Questions 11, 12, 23. Please soon.

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Answered by AJAYMAHICH
1

Step-by-step explanation:

11.

lim (ax^2+bc+c/cx^2+bx+1) at x tends to 1

= (a(1)^2+b(1)+c)/(c(1)^2+b(1)+a)

= (a+b+c)/(c+b+a)

= 1

12.

Lim (1/x + 1/2) / x+2 limit x tends to -2

(0/0) form :-

Lim (x+2)/2x / x+2 = Lim 1/2x

= 1/2(-2)

= -1/4

23.

Lim f(x) limit x tends to 1

Lim f(x) limit x tends to 0

f(x) = (2x+3) where x less than equal to zero {means x tends to zero)

f(x) = 3(x+1) where x greater than to zero {means x tends to one }

Lim 3(x+1) limit x tends to 1

= 3(1+1)

= 6

Lim (2x+1) limit x tends to 0

= 2(0)+1

= 1

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