Question

.Questions 2 cos x + 3 sin x *(i) Evaluate dx 4 cos x + 5 sinx​​

Answer 1

Answer:

tf 2cos(x) + 3sin(x) 4cos(x) + 5sin(x) w let numerator d ɔs(x) + 3sin(x) = A(- (4cos(x) + dx n(x)) + B(4cos(x) + 5sin(x)) solving this we get -2 41 = andB erefore, 23 41 dx = I

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-2 41 (-4sin(x) + 5cos(x)) 4cos(x) + 5sin(x) 23 41 + (4cos(x) + 5sin(x) 4cos(x) + 5sin(x)

-2 dt 23 S + 11 t 41 s dx here t = 4cos(x) + 5sin(x) -2 23 41 Int+ 41 X+C

-2 11 In 14cos(x) + 5sin(x)] + 23 41 X + C

Answer 2

Answer:

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