questions (a) tangent one
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in triangle obp and triangle orp
ob=or. radius
bp=or. op is the bisector of angle bpr
angle bpo=angle rpo
therefore the triangles are congruent to each other
so op equals ob by cpct
angle obp equals 90 therefore angles bpo and bop are 45
similarly orq and oqa are congruent
therefore oaq is 90 and angle aoq and oqa are 45...
so angle qop equals 180-(angle qoa and angle pob)=180-(45+45)=90
therefore angle qop is 90 and op and oq are perpendicular to each other.......proved
pls mark me the brainliest...
ob=or. radius
bp=or. op is the bisector of angle bpr
angle bpo=angle rpo
therefore the triangles are congruent to each other
so op equals ob by cpct
angle obp equals 90 therefore angles bpo and bop are 45
similarly orq and oqa are congruent
therefore oaq is 90 and angle aoq and oqa are 45...
so angle qop equals 180-(angle qoa and angle pob)=180-(45+45)=90
therefore angle qop is 90 and op and oq are perpendicular to each other.......proved
pls mark me the brainliest...
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