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Given :
- Total Families = 1500
To Find :
- Probability of a family chosen at random having (i) 2 girl
- (ii) 1 girl
- (iii) No girl
Solution :
(i) 2 girl :
So , The Probability of getting 2 girl is 19/60 ..
_______________________
(ii) 1 girl :
So , The Probability of getting 2 girl is 407/750 ..
_______________________
(iii) 0 girl :
So , The Probability of getting 0 girl is 211/1500 ..
Answer:
Given :
Total Families = 1500
To Find :
Probability of a family chosen at random having (i) 2 girl
(ii) 1 girl
(iii) No girl
Solution :
\longrightarrow\tt{Total\:Outcomes=1500}⟶TotalOutcomes=1500
(i) 2 girl :
\longmapsto\tt{Favourable\:Outcomes=475}⟼FavourableOutcomes=475
\longmapsto\tt{Probability=\frac{No.\:of\:Fav.\:Outcomes}{Total\:No.\:of\:Outcomes}}⟼Probability=
TotalNo.ofOutcomes
No.ofFav.Outcomes
\longmapsto\tt{\cancel\dfrac{475}{1500}}⟼
1500
475
\longmapsto\tt\bf{\dfrac{19}{60}}⟼
60
19
So , The Probability of getting 2 girl is 19/60 ..
_______________________
(ii) 1 girl :
\longmapsto\tt{Favourable\:Outcomes=814}⟼FavourableOutcomes=814
\longmapsto\tt{Probability=\frac{No.\:of\:Fav.\:Outcomes}{Total\:No.\:of\:Outcomes}}⟼Probability=
TotalNo.ofOutcomes
No.ofFav.Outcomes
\longmapsto\tt{\cancel\dfrac{814}{1500}}⟼
1500
814
\longmapsto\tt\bf{\dfrac{407}{750}}⟼
750
407
So , The Probability of getting 2 girl is 407/750 ..
_______________________
(iii) 0 girl :
\longmapsto\tt{Favourable\:Outcomes=211}⟼FavourableOutcomes=211
\longmapsto\tt{Probability=\frac{No.\:of\:Fav.\:Outcomes}{Total\:No.\:of\:Outcomes}}⟼Probability=
TotalNo.ofOutcomes
No.ofFav.Outcomes
\longmapsto\tt\bf{\dfrac{211}{1500}}⟼
1500
211
So , The Probability of getting 0 girl is 211/1500 ..
Step-by-step explanation:
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