Math, asked by Anonymous, 1 year ago

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shahaana: 15=10√3
sachin1121195: go to my question
sachin1121195: in ny this id
sachin1121195: plzz

Answers

Answered by vampire002
4
hey mate here is your answer ✌⛄

15) side=10cm

longest rod = diagonal=√3(side)

=10√3cm

so option d is correct

16) diagonal=8√3cm

so side= 8√3/√3

=8cm

so surface area= 6side²

=(6)8²

=64×6cm²

=384cm²

so option b is correct

17) side=x cm

increase side=X/2 + X

=3x/2 cm

so surface area=6x²

increase surface area=6(9x²/4)

=27x²/2

increase=(27x²/2) -6x²

=15x²/2

so percentage=15x²/2/6x²×100

=15/2 ×100

so = 125%

so option d is correct

18) volume of new cube= V1+v2+v3

L ³=l1³+l2³+l3³

L³=3³+4³+5³

=21600

l=6cm

so LSA=4l²

=4(6)²

=4×36

=144cm²

so option b is correct

hope it will help you ☃⛄

mark me brainliest ✌✌⛄

vampire002: sry wait
vampire002: i will edit it
vampire002: now it is whole required answer
Anonymous: thanks a lot ^_^
vampire002: ✌^_^✌
Anonymous: nice
Answered by ShuchiRecites
4
Hello sis!

15. You have to focus that diagonal is the longest length in any 3D shape.

So, diagonal of cube = √3( side )

Since side of cube is 10 cm.

Diagonal = 10√3 cm

Thus, longest rod that can fit must be 10√3 cm long.

Answer : Option (D).

16. Since diagonal of cube = √3(side)

8√3 cm = √3(side)

8 cm = side

Surface area of cube = 6(side)²

= 6 × 8² = 384 cm²

Answer : Option (B).

17. Let the edge of cube be x.

Surface area = 6x²

Now each side is increased by 50%

So, new side = x + 50x/100 or x + x/2 or 3x/2

Surface area = 6(3x/2)² = 6 × 9x²/4

= 27x²/2

Surface area increased = 27x²/2 - 6x²

= ( 27 - 12 )x²/2 = 15x²/2

Percentage increased = [ (15x²/2) / (6x²) ] × 100

= 125%

Answer : Option (D).

18. Volume of each cube = 3³ = 27 cm³

= 4³ = 64 cm³

= 5³ = 125 cm³

Total volume = ( 27 + 64 + 125 ) cm³

= 216 cm³

Volume of large cube = Side³

216 cm³ = side³

6 cm = side

Lateral ( area if 4 walls ) surface area = 4(side)²

= 4 × 6² = 144 cm²

Answer : Option (B).

Have great future ahead!

Anonymous: thanks a lot..☺
ShuchiRecites: Always welcome sisu
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