Question

Questions my answers ​

Answer 1

Answer:

<spr = <pqr + <prq                                                        (exterior angle property)

135⁰ = (180⁰ - < pqt ) + <prq                                                               (linear pair)              

135⁰- 70⁰ = <prq

65⁰ = < prq

Step-by-step explanation:

hope it helps

Answer 2

Given :

• ∠SPR = 135°
• ∠PQT = 110°

To Find :

• ∠PRQ

Solution :

$\longmapsto\tt{\angle{PQT}+\angle{PQR}=180^{\circ}}$

$\longmapsto\tt{110^{\circ}+\angle{PQR}=180^{\circ}}$

$\longmapsto\tt{\angle{PQR}=180^{\circ}-110^{\circ}}$

$\longmapsto\tt\bold{\angle{PQR}=70^{\circ}}$

Now ,

$\longmapsto\tt{\angle{SPR}=\angle{PQR}+\angle{PRQ}\:(Exterior\:angle)}$

$\longmapsto\tt{135^{\circ}=70^{\circ}+\angle{PRQ}}$

$\longmapsto\tt{135^{\circ}-70^{\circ}=\angle{PRQ}}$

$\longmapsto\tt\bold{\angle{PRQ}=65^{\circ}}$

Therefore :

$\longmapsto\tt\bf{\angle{PQR}=70^{\circ}}$

$\longmapsto\tt\bf{\angle{PRQ}=65^{\circ}}$