Questions no. 11 solve
And and solve your copy I can't understand on phone so please
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anitasurendra123:
Please solve 12
S6 =42
a + 9d 1
------------ = -------
a + 29d 3
cross multiply we get
3a + 27d = a +29 d
2a - 2d = 0 ------------------ (1)
its given that
sum of first six terms of an AP is 42
therefore
S6 = n/2 ( 2a + (n-1) d)
42 = 6/2 ( 2a + (6-1) d)
42 = 3 (2a + 5d )
14 = 2a +5d
2a +5d = 14 ------------------- (2)
solve eq 1 and 2
2a - 2d = 0
2a +5d = 14
we get
d= 2
a = 2
a + 9d 1
------------ = -------
a + 29d 3
cross multiply we get
3a + 27d = a +29 d
2a - 2d = 0 ------------------ (1)
its given that
sum of first six terms of an AP is 42
therefore
S6 = n/2 ( 2a + (n-1) d)
42 = 6/2 ( 2a + (6-1) d)
42 = 3 (2a + 5d )
14 = 2a +5d
2a +5d = 14 ------------------- (2)
solve eq 1 and 2
2a - 2d = 0
2a +5d = 14
we get
d= 2
a = 2
answer is 2
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I want to know
It's sample paper you can see in pic
Yes u at right it's a sample paper
hy Anita
ya may be
hlo
But how can I send the answer by completing square method .ihave done it too
U are
Yes I have done it
which sample paper u take this question
Answered by
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I think this will help uu
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