questions no. 8 give me answer fast and follow me
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f ( x ) = x^n + a^n
x + a = 0 => x = -a
f ( -a ) = ( -a )^n + a^n = 0
When n = even, -a becomes positive and does not fulfill the condition.
When n = odd, -a remains negative and fulfills the condition.
Therefore, x + a is a factor of x^n + a^n when n is an odd number.
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