Question

QUESTIONS NUMBER 8 FAST ​

Answer 1

For points to be collinear area of triangle made by the vertices is 0.

So (3k-1)(k-7-k+2) + k(k-2-k+2) + (k-1)(k-2-k+7)=0

=> (3k-1)(-5) + 0 + 5(k-1)=0

=> -15k + 5+5k -5=0

=> -10k = 0

:. k= 0 is the solution...