Math, asked by designhawkraj, 3 months ago

QUESTIONS
One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting a
red card. please tell ​

Answers

Answered by Cynefin
95

Required Answer:-

In a deck of cards, there are 26 red cards and 26 black cards. The red cards include:

  • Diamond cards (13) &
  • Heart cards (13)

And the black cards include:

  • Spade cards (13)
  • Club cards (13)

We to need to find the probability of getting red cards from the deck of cards.

  1. Possible outcomes (Red card) = 26
  2. Total outcomes = 52

Then, probability is given by:

\underline{\boxed{ \rm{P(E) =  \frac{Possible  \: outcomes \:  of  \: the  \: event}{Total  \: outcomes.}}}}

Plugging the values:

➙ P(Red cards) = 26/52

➙ P(Red cards) = 1/2 or 0.5 (Required probability)

Answered by BrainlyRish
71

Given : One card is drawn from a well-shuffled deck of 52 cards .

Exigency To Find : The probability of getting a red card .

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

Given that ,

⠀⠀⠀One card is drawn from a well-shuffled deck of 52 cards. .

\rule{200}2

⠀⠀⠀Finding the Probability of getting a red card from a well-shuffled deck of 52 cards :

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

⠀For this first we should know there are how many and what type of cards in a Deck ;

⠀⠀⠀A standard deck of playing cards contains 52 cards .

⠀⠀⠀Here ,

⠀⠀⠀⠀⠀⠀The no. of Black cards are 26 cards , in which ,

⠀⠀⠀⠀⠀⠀⠀⠀⠀▪︎⠀There are 13 Spades Cards ( )

⠀⠀⠀⠀⠀⠀⠀⠀⠀▪︎⠀There are 13 Clubs Cards ( )⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀&

⠀⠀⠀⠀⠀⠀The no. of Red cards are 26 cards , in which ,

⠀⠀⠀⠀⠀⠀⠀⠀⠀▪︎⠀ There are 13 Hearts Cards ( )

⠀⠀⠀⠀⠀⠀⠀⠀⠀▪︎⠀There are 13 Diamonds Cards ( )

\rule{200}2

\dag\:\:\sf{ As,\:We\:know\:that\::}\\\\\qquad\maltese \:\:\bf Formula\:for\: Probability\:\;:\\\\

\qquad \dag\:\:\bigg\lgroup \sf{Probability \:: \dfrac{ Favorable \:Outcome }{Total\:Outcome }}\bigg\rgroup \\\\

⠀⠀⠀⠀⠀⠀⠀Here ,

  • Favorable Outcome : The no. of Red cards is 26
  • Total Outcomes : The no. of cards in a deck is 52

⠀⠀⠀⠀⠀⠀\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}\\

\qquad:\implies \sf Probability_{(Red \:Cards\:)} \:=\:  \dfrac{ Favorable \:Outcome }{Total\:Outcome }\\

\qquad:\implies \sf Probability_{(Red\:Cards \:)}\:=\:  \dfrac{ 26 }{52}\\

\qquad:\implies \sf Probability_{(Red\:Cards \:)} \:=\: \cancel {\dfrac{ 26 }{52}}\\

\qquad:\implies \sf Probability_{(Red\:Cards \:)} \:=\:  \dfrac{1}{2}\\

\qquad:\implies \bf Probability_{(Red\:Cards \:)} \:=\:  \dfrac{ 1 }{2}\:\:or\;\:0.5\:\\

\qquad:\implies \frak{\underline{\purple{\: Probability_{(Red\:Cards \:)} \:=\:  \dfrac{ 1 }{2}\:\:or\;\:0.5\:}} }\:\:\bigstar \\

Therefore,

⠀⠀⠀⠀⠀\therefore {\underline{ \mathrm {\:The\:Probability \:of\:getting \:red\:cards\:is\:\bf{ \dfrac{ 1 }{2}\:\:or\;\:0.5\: .}}}}\\

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

⠀⠀⠀⠀⠀⠀⠀⠀

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