Questions to be solved......plz help me in maths...
1...A company packs chocolate powder in cylinderical jars of radius 7 cm and height 20 cm. The label of company is placed around the surface of jar with a 2cm space from top and bottom. Find area õf label..
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Diameter of the container = 14 cmRadius = 7 cm Height of the container = 20 cm Curved surface area of the container = 2πrh = 2 x 22/7 x 7 x 20 = 880 cm2 Height of the label = 20 - (2 x 2) = 20 - 4 = 16 Area of the label = 2πrh = 2 x 22/7 x 7 x 16 = 704 cm2 Hence, area of the label is 704 cm2.
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Solution:---
➡Curved surfacw area of cylinder = 2Πrh
➡the label is too be wrapped around the jar while leaving a space of 2cm upside and 2cm downside
so height of label = 20-4=16cm
Area of Wrapped label = 2Πr(16)
= 2 x 3.14 x 7 x 16
= 2 x 3.14 x 7 x 16
² [approx ~704]
is the answer
➡Curved surfacw area of cylinder = 2Πrh
➡the label is too be wrapped around the jar while leaving a space of 2cm upside and 2cm downside
so height of label = 20-4=16cm
Area of Wrapped label = 2Πr(16)
= 2 x 3.14 x 7 x 16
= 2 x 3.14 x 7 x 16
² [approx ~704]
is the answer
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