Question

Questions
Two bodies of 6 kg and 4 kg masses have their
velocity 5i - 2j+10k and 101 – 2j +5,
respectively. Then, the velocity of centre of ma
(a) 5i + 2j - 8 (b) 7 + 2j - 8
(c) 7î - 2j +8ſ (d) 5î - 2j + 8k​

Answer 1

Given:

$m_{1}=6kg$

$m_{2}=4kg$

$v_{1}=5i-2j+10k$

$v_{2}=10i-2j+5k$

To find:

$V_{com}$

Explanation:

$m_{1$=mass of first body

$m_{2$=mass of second body

$v_{1$=velocity of first body

$v_{2$=velocity of second body

$V_{com$=Velocity of center of mass

$V_{com$ is given by:

$V_{com=\frac{m_{1}v_{1}+m_{2}v_{2} }{m_{1}+m_{2}}$

$V_{com$=$\frac{6(5i-2j+10k)+4(10i-2j+5k)}{6+4}$

$V_{com}=\frac{70i-20j+80k}{10}$

$V_{com}=7i-2j+8k$ = Final answer