Math, asked by agarwaldeepa941, 8 months ago

Questions
which the
find the value
System
of Equestions you
at 3
= 5
KX + gy
hey infinitely many solutione​

Answers

Answered by dhayana36
0

Answer:

ANSWER

Given

kx−y=2

6x−2y=3

kx−y−2=0

6x−2y−3=0

We know that for a

1

x+b

1

y+c

1

=0,a

2

x+b

2

y+c

2

=90

a

2

a

1

=

b

2

b

1

=

c

2

c

1

⇒ for no solution

a

1

=k,b=−1,c

1

=−2

a

2

=b,b

2

=−1,c

2

=−3

6

k

=

−2

−1

=

−3

−2

6

k

=

2

1

=

3

2

for no solution

6

k

=

2

1

nd

2

1

=

3

2

⇒k=

2

6

k=3

for infinite solution

b

1

a

1

=

b

2

b

1

=

c

2

c

1

b

k

=

−2

−1

=

−3

−2

+2

+1

=

−3

+2

=

2

1

=

3

2

Here is no value of k the system has infinite solution.

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