queston no. 9 plzz give the answer
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Hey !!
let the required no. x
using uclids division lemma .
x = 28p + 8
and x = 32q + 12 [ where p and q is questiont]
=> 28p + 8 = 32q + 12
=> 28p - 32q = 12-8
=> 28p = 4 + 32q
=> 4 × 7p = 4 ( 1 + 8q)
=> 7p = 1 + 8q -------1)
Here p = 8n - 1 and q = 7n-1 stisfies 1)
where n is natural no.
on putting n = 1
p = 8n - 1 = 7
.and q = 7n - 1 = 6
Thus , x = 28p + 8
=> 28×7 + 8
=> 204 Answer
hence , the smallest no. which divides 28, 32 which leaves remainder 8 and 12 is 204
Hope it helps you !!
@Rajukumar111
let the required no. x
using uclids division lemma .
x = 28p + 8
and x = 32q + 12 [ where p and q is questiont]
=> 28p + 8 = 32q + 12
=> 28p - 32q = 12-8
=> 28p = 4 + 32q
=> 4 × 7p = 4 ( 1 + 8q)
=> 7p = 1 + 8q -------1)
Here p = 8n - 1 and q = 7n-1 stisfies 1)
where n is natural no.
on putting n = 1
p = 8n - 1 = 7
.and q = 7n - 1 = 6
Thus , x = 28p + 8
=> 28×7 + 8
=> 204 Answer
hence , the smallest no. which divides 28, 32 which leaves remainder 8 and 12 is 204
Hope it helps you !!
@Rajukumar111
nitthesh7:
Here p = 8n - 1 and q = 7n-1 stisfies 1) How bro..
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