Question

Quesuun 2 a) Factorise : m(x - y)² – ny + nx +3x -3y ​

Answer 1

( mx² - my² ) - ny + 3x - 3y

( mx + my ) ( mx - my ) - ny + 3x - 3y

Now , let ( mx + my ) ( mx - my ) be "xn" , then :

xn - ny + 3x - 3y

n ( x - y ) + 3 ( x - y )

( n + 3 ) ( x - y )

( mx + my +3 ) ( mx - my + 3 ) ( x - y )

Step-by-step explanation:

thanks.