Quesuun. 2
When a lithium-7 nucleus is bombarded by a proton, two alpha particles are produced. The Q value is
(1H1: 1.007825 u, 2He4: 4.002603 u, 3Li7: 7.016004 u)
0 -17.35 MeV
O +17.35 MeV
+27.35 MeV
0 -27.35 MeV
SAS
Answers
Answered by
3
Given:
1H1=1.008
2He4=4.003
3Li7=7.016
To find:
The Q- value
Solution:
The formula of Q is
Q= Δm×931 MeV
Q=[m(Li)+m(H)-2m(He)]×931
Q=[7.016+1.008-2×4.003]×931
Q=0.016×931
Q=14.896 MeV
So, the value of Q is 14.896 MeV
Answered by
3
Answer:
Given:
1H1=1.008
2He4=4.003
3Li7=7.016
To find:
The Q- value
Solution:
The formula of Q is
Q= Δm×931 MeV
Q=[m(Li)+m(H)-2m(He)]×931
Q=[7.016+1.008-2×4.003]×931
Q=0.016×931
Q=14.896 MeV
So, the value of Q is 14.896 MeV
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