quick bro with full explanation☝️
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3
Answer:
Step-by-step explanation:
x²-x-2
x²-2x+x-2
x(x-2)+1(x-2)
(x-2)(x+1)
x=2, x= -1
Alpha=2 beeta= -1
x²-(alpha+beeta)x + alphaXbeeta)
x²-(5-1)x+(5)(-1)
(Zeroes are 2alpha+1 and 2beeta +1)
x²-4x-5
Answered by
2
Hey mate...
Thank you for asking this question. Here is your answer:
x²-3x+2=0
=x²-x-2x+2=0
=x(x-1)-2(x-1)=0
(x-1)(x-2)=0x=1
or ,
x=2 given zeroes of quadratic polynomial 1/2alpha+beta
1/2beta+alpha substitute=1/2(1)+2
1/2(2)+1=1/4
1/5formula is x²-(alpha+beta)x+alpha*beta =0therefore x²-
(1/4+1/5)x+1/4*1/5=0=ans is 20x^2 - 9x +1 =0
Hope this helps you
Long time meeting....
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