Question

quick bro with full explanation☝️​

Answer 1

Answer:

Step-by-step explanation:

x²-x-2

x²-2x+x-2

x(x-2)+1(x-2)

(x-2)(x+1)

x=2, x= -1

Alpha=2 beeta= -1

x²-(alpha+beeta)x + alphaXbeeta)

x²-(5-1)x+(5)(-1)

(Zeroes are 2alpha+1 and 2beeta +1)

x²-4x-5

Answer 2

Hey mate...

Thank you for asking this question. Here is your answer:

x²-3x+2=0

=x²-x-2x+2=0

=x(x-1)-2(x-1)=0

(x-1)(x-2)=0x=1

or ,

x=2 given zeroes of quadratic polynomial 1/2alpha+beta

1/2beta+alpha substitute=1/2(1)+2

1/2(2)+1=1/4

1/5formula is x²-(alpha+beta)x+alpha*beta =0therefore x²-

(1/4+1/5)x+1/4*1/5=0=ans is 20x^2 - 9x +1 =0

Hope this helps you

Long time meeting....