quick i need this answer. if one angle of a parallelogram is 4/5th of thd adjacent angle. find all the angles of the parallelogram
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let the angles be x and 4x/5 .
we know that x+(4x/5) =180° (they're co interior angles)
multiplying both sides by 5,
5x+4x=900°
9x= 900°
x=100°
so the two angles are 80° and 100°.
divergent07:
good
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