Question

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by equation
s=ut+1/2at^2​

Answer 1

Explanation:

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Answer 2

ANSWER

Given that,

Acceleration a=−0.5m/s2

Speed v=90km/h=25m/s

Using equation of motion, 

v=u+at

Where, 

v = final velocity

u = initial velocity

a = acceleration

t = time

Put the value into the equation

Finally train will be rest so, final velocity,v=0

0=25−0.5t

25=0.5t

t=25/0.5

t=50 sec

Again, using equation of motion, 

S=ut+(at^2)/2

Where, s = distance

v = final velocity

u = initial velocity

a = acceleration

t = time

Put the value into the equation

Where S is distance travelled before stop

s=25×50−[×0.5×(50)^2]/2

s=625 m

So, the train will go before it is brought to rest is 625 m.

Explanation:

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