Question

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find only the distance from equation
2as=v^2-u^2​

Answer 1

Explanation:

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Answer 2

Answer:

HERE IS YOUR ANSWER

Explanation:

initial speed = u = 18 km/hr = 5 m/s

Final speed = v = 36 km/hr = 10 m/s

acceleration a = (v-u)/t = (10-5)/5 = 1 m/s^2 Distance travelled S =

u t + (1/2) a t2 = 5×5 + (1/2)×1×52 = 37.5 m

using 2as=v^2-u^2 ........

2as = v^2-u^2

2×1×s = (10)^2-(5)^2

2s = 100-25

2s = 75

s= 75/2=37.5.........

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