Question

quick way to split middle term with 3 digits
e.g. 116x^2-88x+15=0
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Answer 1

$116 {x}^{2} \underline{ - 88x }+ 15 = 0 \\ \\ \implies116 {x}^{2} \underline{ - 58x - 30x} + 15 = 0 \\ \\ \implies58x(2x - 1) - 15(2x - 1) = 0 \\ \\ \implies(2x - 1)(58x - 15) = 0 \\ \\ \implies(2x - 1) = 0 \: or \: (58x - 15) = 0 \\ \\ \implies \: x = \frac{1}{2} or \: x = \frac{15}{58}$