Question

Quiz
A simple pendulum is suspended from the ceiling of a stationary elevator, and the period
is measured. If the elevator moves with constant velocity, does the period (a) increase
(b) decrease, or (c) remain the same? If the elevator accelerates upward, does the
period (a) increase, (b) decrease, or (c) remain the same?​

Answer 1

Answer:

if the elevator moves with constant velocity

period remains same(c)

Explanation:

if it accelerates its speed increases with time period (a)

thanks

Answer 2

Answer:

1) remain same

2) decrease

Explanation:

we know T = 2π√l/√g

in first case : velocity is constant that gives us zero acceleration, so there is no change in acceleration due to gravity.

in second case: acceleration is upward so a net acceleration due to gravity will be (g+a) downwards.

since T is inversely proportional to g

T is inversely proportional to g so if g increases then T will decrease.