Question

Quiz
A simple pendulum is suspended from the ceiling of a stationary elevator, and the period
is measured.If the elevator accelerates
upward, does the
period (a) increase, (b) decrease, or (c) remain the same?

Answer 1

Explanation:

We know that the time period of a simple pendulum, T = 2π(√L/g) where, L = length of the string g = acceleration due to gravity as there are no other forces are acting Case: When the elevator is moving with constant velocity : That is, there is no acceleration in the elevator. i.e. a = 0 T = 2π\sqrtL/(g+0) = 2π(√L/g) Thus, answer will be (c) remains the same. Case: When the elevator is moving...