Question

Qus. 10: find the volume, curved surface area and total surface area of the cylinder whose height and radius of the base are 14 cm and 4 cm respectively.​

Answer 1

Given that, height (h) of cylinder is 14cm and radius (r) is 4 cm.

Then, the volume of the cylinder is :

$π {r}^{2} h$

= $\frac{22}{7} \times {4}^{2} \times 14\: {cm}^{3}$

= $\frac{22 \times 4 \times 4 \times 14}{7} \: {cm}^{3}$

= $22 \times 4 \times 4 \times 2\: {cm}^{3}$

=$704\: {cm}^{3}$

And, the curved surface area is :

$2πrh$

= $2 \times \frac{22}{7} \times 4 \times 14 \: {cm}^{2}$

= $2 \times 22 \times 4 \times 2 \: {cm}^{2}$

= $352 \: {cm}^{2}$

And, the total surface area is :

$2πr(r + h)$

= $2 \times \frac{22}{7} \times 4 \times (4 + 14) \: {cm}^{2}$

= $\frac{2 \times 22 \times 4 \times 18}{7} \: {cm}^{2}$

=$452.571428571........ \: {cm}^{2}$

Hope, it will help you.

Answer 2

Cylinder, radius of base = 7 cm.

Cylinder, height = 50 cm.

Cylinder, volume = (22/7)*7^2*50 = 7700 c c.

Cylinder, curved surface area = 2*(22/7)*7*50 = 2200 sqcm.

Cylinder, area of base and top = 2*(22/7)*7^2 = 308 sq cm.

Cylinder, total surface area = 2200 + 308 = 2508 sq cm.