Question

Qus. 4. The angle of elevation of the top of a
Tower from a point on the ground, which is 30 m
away from the foot of the tower, is 30°. Find the
height of the tower.​

Answer 1

Answer:

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Answer 2

$\LARGE\star\mathfrak{\underline{\underline{\red{answer: }}}}$

ɪɴ ∆ᴀʙᴄ,

$tan \theta = \frac{AB}{BC} \\ \\ tan \: 30 \degree = \frac{h}{30} \\ \\ \frac{1}{ \sqrt{3} } = \frac{h}{30} \\ \\ h \sqrt{3} = 30 \\ \\ h = \frac{30}{ \sqrt{3} } \\ \\ h = \frac{30}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } \\ \\ h = \frac{ \cancel{30 }\sqrt{3} }{ \cancel3} \\ \\ \boxed {\sf h = 10 \sqrt{3} \: m}$

height of the tower is 10√3 m