Question

R(0,3). D(2, 1), 5(3,-1) (4) P(-2, 3), (1.2), R(4.)
3. Find the point on the X-axis which is equidistant from AC-3, 4) and B(1, -1).
rify that points
( 2)​

Answer 1

The point C (2.8,0) is lie on the axis, which is equidistant from A(-3, 4) and B(1, -1)

Step-by-step explanation:

Given :

A(-3,4) and B(1,-1)  are the given points

As the point is on X-axis its co - ordinates are C(x,0)

AC = BC , C(x,0) equidistant from A(-3,4) and B(1,-1)

$\text{Distance Formula} = \sqrt{(\text{x}_2 - \text{x}_1)^2 + (\text{y}_2 - \text{y}_1)^2}$

                     $\text{AC} = \sqrt{(\text{x} - (-3))^2 + (0 - 4)^2}$

                      $\text{BC} = \sqrt{(\text{x} - 1)^2 + (0 + 1)^2}$

Squaring on both sides to remove square root

AC² = BC²

(x +3)²+(-4)² = (x-1)²+(1)²

x²+6x+9+16 = x²-2x+1+1

x²+6x+25=x²-2x+2

6x+2x=2-25

8x= - 23

$\text{x} = \frac{-23}{8}$

$\text{x} = -2.8$

The point on the X- axis which is equidistant from A(-3, 4) and B(1, -1) is   C(2.8,0)

To Learn More....

1. Obtain the equation of the line parallel to the x axis and making an intercept of 3 unit on the y axis

brainly.in/question/13648622

2. In what ratio does the x-axis cut the line segment joining( 5,8) and (7, -3)?

brainly.in/question/12098282